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16x-2=6x^2
We move all terms to the left:
16x-2-(6x^2)=0
determiningTheFunctionDomain -6x^2+16x-2=0
a = -6; b = 16; c = -2;
Δ = b2-4ac
Δ = 162-4·(-6)·(-2)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{13}}{2*-6}=\frac{-16-4\sqrt{13}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{13}}{2*-6}=\frac{-16+4\sqrt{13}}{-12} $
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